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2x^2+3=44-2
We move all terms to the left:
2x^2+3-(44-2)=0
We add all the numbers together, and all the variables
2x^2+3-42=0
We add all the numbers together, and all the variables
2x^2-39=0
a = 2; b = 0; c = -39;
Δ = b2-4ac
Δ = 02-4·2·(-39)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{78}}{2*2}=\frac{0-2\sqrt{78}}{4} =-\frac{2\sqrt{78}}{4} =-\frac{\sqrt{78}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{78}}{2*2}=\frac{0+2\sqrt{78}}{4} =\frac{2\sqrt{78}}{4} =\frac{\sqrt{78}}{2} $
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